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Critical Points and Where They Occur

Simple Explanation

A critical point of a function f is any x-value where f'(x) = 0 or where f'(x) does not exist. These are the only places a local maximum or local minimum can occur β€” the function's graph is momentarily flat (or has a sharp corner) there.

Why Do We Need It?

Critical points narrow down an infinite number of x-values to a short, finite list of candidates β€” turning "where is this function largest or smallest?" from an impossible search into a few calculations.

See It

The graph of f(x) = xΒ³ βˆ’ 3x, with its two critical points marked
-2-2-1-111220xycritical point (βˆ’1, 2)critical point (1, βˆ’2)

A cubic curve that rises to a peak near x=βˆ’1, dips down to a valley near x=1, marked with dots at both points

Formula

The Definition of a Critical Point

A critical point of f occurs where f'(x) = 0, or where f'(x) is undefined

Critical points are the candidate locations for local maxima, local minima, or other notable features of a function's graph.

f'(x)
β€” the derivative of f

When to use it: Whenever locating a function's local extrema (maxima/minima) is the goal β€” always start by finding the critical points.

Worked Example

Find the critical points of a cubic

Find all critical points of f(x) = xΒ³ βˆ’ 3x.

    Why Does This Work?

    At a smooth local maximum or minimum, the tangent line must be exactly horizontal β€” any nonzero slope means the function is still rising or falling, and could not yet be at a peak or valley β€” so f'(x)=0 is a necessary condition. Where f'(x) does not exist (a sharp corner), the function can still turn around there, so those points must be checked too.

    Real-Life Example

    The peak height of a thrown ball

    A ball's height over time rises, momentarily stops rising at its peak, then falls.

    That exact instant β€” where the height function's derivative (its velocity) equals zero β€” is a critical point, and it is exactly where the ball reaches its maximum height.

    Practice

    Find the critical point of f(x) = xΒ² βˆ’ 4x + 1 (give the x-value).

    Easy

    For f(x) = xΒ³ βˆ’ 3x, what is the y-coordinate of the critical point at x = 1?

    Medium

    Common mistake

    Substituting the critical x-value back into f'(x) instead of f(x) when finding the point's y-coordinate β€” f'(x) is exactly 0 there by construction, which is not the point's height.

    Quick Review

    • Critical points: where f'(x)=0 or f'(x) is undefined.
    • They are the only candidates for local maxima and minima.
    • Always substitute back into f (not f') to get the point's y-coordinate.