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Hard

Applications of Implicit Differentiation

Simple Explanation

Implicit differentiation extends naturally to more complex equations relating x and y, including ones with an xy term β€” which needs the Product Rule (since it's a product of x and the function y) combined with the Chain Rule.

Why Do We Need It?

This combines every differentiation rule from this chapter into one technique β€” a genuine test of whether the Power, Product, and Chain Rules are all understood together.

Formula

Implicit Differentiation

Differentiate both sides w.r.t. x; for every y-term, multiply by dy/dx (Chain Rule)

When y is not isolated on one side of an equation, differentiate both sides of the equation with respect to x directly, treating y as an unknown function of x β€” every time a y appears, its derivative contributes a dy/dx factor by the Chain Rule.

dy/dx
β€” the derivative of y with respect to x β€” the very thing being solved for

When to use it: Whenever an equation relates x and y together, but y cannot easily be isolated as y = (some function of x).

Worked Example

Implicitly differentiate an equation with an xy term

Given xΒ² + xy + yΒ² = 7, find dy/dx at the point (1, 2).

    Why Does This Work?

    The xy term genuinely needs the Product Rule because it is a product of two quantities that both change with x β€” the variable x itself, and the (implicit) function y(x). Treating xy as a simple power of x would be incorrect, since y is not constant.

    Real-Life Example

    Related rates in a system defined by an implicit constraint

    A physical system (e.g. two connected quantities in a mechanism) obeys a constraint equation relating x and y that cannot be solved cleanly for y.

    Applications of implicit differentiation β€” including the Product Rule for mixed xy terms β€” are exactly the technique used to find how fast one quantity changes as the other does, in these "related rates" problems.

    Practice

    For xΒ² + xy + yΒ² = 7, find dy/dx at the point (2, 1).

    Hard

    Common mistake

    Differentiating the xy term as if it were just xΒ² or yΒ² alone β€” a mixed term like xy always needs the Product Rule, since it is genuinely a product of two things that both depend on x.

    Quick Review

    • A mixed xy term needs the Product Rule: d/dx[xy] = y + xΒ·(dy/dx).
    • Group all dy/dx terms together, then factor and solve algebraically.
    • Combines the Power, Product, and Chain Rules into a single technique.